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## Analysing Specific Capacity and Energy Density of some popular batteries

In my last article, I was concentrating more about the Specific Capacity of different cathode materials. But this is only one part of the story when a complete cell is concerned. To find the Specific Capacity of a particular battery chemistry the whole chemical reaction has to be analyzed.

Essentially the method used here is similar to that of previous analysis. Instead of just the cathode material, we have to consider the complete chemical reaction taking place in both cathode and anode. But the rest of the calculation is nearly the same. In short,
```Specific Capacity = (N x F) / (Total weight of all components) where, N = Change in oxidation state or the number of electrons released. F = Faraday constant, 26801mAh/Mole ```

This is one of the oldest rechargeable batteries invented, yet ubiquitous. The following is the chemical reaction happening in both Cathode and Anode during discharge process.
-ve Electrode: Cathode: Pb + H2SO4 = PbSO4 + 2H+ + 2e
+ve Electrode: PbO2 + H2SO4 + 2H+ = PbSO4 + 2H2O
The total chemical reaction is,
`Pb + PbO2 + 2 H2SO4 = 2 PbSO4 + 2H2O (with 2 electrons through circuit)`
Finding the total molar weight, 643g of reactants produce 2 Moles of electrons.``` Specific Capacity = 2 * 26.801/643 = 83mAh/g Total Energy Density, assuming 2V per reaction = 166 Wh/g ```

Lithium Ion (Lithium Ferrous Phosphate):
This is one of the variants in the family of Lithium Ion Battery.
Overall Chemical reaction during reaction is as follows
`LiC6 + FePO4 = LiFePO4 + 6C (with 1 electron through circuit)`
That means 230g of reactants produce 1 Mole of electrons, at 3.3V
Calculating both Specific Capacity and Energy Density
```Specific Capacity = 26.801/230 = 117mAh/g Energy Density = 385Wh/kg```

Sodium Sulphur:
Mainly used in grid scale energy storage application, Sodium Sulphur is a variant of molten metal battery.
To give the overall chemical reaction,
`2Na + 4S = Na2S4 (with 2 electrons through circuit)`
The cell gives out 2V.
In this case, 174g of reactants, give out 2 Mole of electrons.
So Specific Capacity and Energy Density are
```Specific Capacity = 308mAh/g Energy Density = 616Wh/kg```

Conclusion:
It could be easily seen that Lead Acid battery, even though most widely used has a very low theoretical capacity. An interesting finding is that, the current practical capacities of both Lithium-Ion and Sodium Sulphur batteries are reaching very near to the theoretical capacity of Lead Acid technology.

## Specific Capacity of Cathode Materials

Recently I read some news about Lithium Ion batteries and the author mentioned that Lithium has the highest Specific Capacity of 3861mAh/g. I was very curious to know where this magic number came from. After trying to understand more about that, finally I found the answer. That was 12th class electrochemistry. The calculation is given below.

`Specific Capacity = (N x F) / (Atomic Weight)`
```where, N = Valency of the Material F = Faraday constant = 96485 Coulombs/Mole```
If this has to be expressed in terms of current, divide that by 3600
`F = 26.801Ah/Mole`

This is how the equation works for Lithium. Faraday constant is nothing but the total charge of Avogadro number of electrons. Since Lithium has a Valency of 1 and atomic weight of 6.94g/Mole, every 6.94g of Lithium would give out Valency times Avogadro number of electrons when ionized. So, to find out the Specific Capacity

```Specific Capacity = (1 Valency x 26.801Ah/g x 1000mA/A) / 6.94g/Mole = 3861mAh/g```

That means, when 1 gram of Lithium metal ionizes to Li+ ions, it gives out 3.861Ah of electricity. This is just the current, but not the energy. If we are interested to calculate the energy density of reaction, it is required to know the Standard Electrode Potential of each material. Since it is 3.03V for Lithium, the total energy density of ionization of Lithium is
`3.03V x 3.861Ah/g * 1000g/kg = 11701Wh/kg.`
This comes very close the values of hydrocarbons.

But, remember this is just a half reaction taking place in the cell. We did not consider the anode reaction at all. So, total Specific Capacity of a complete cell would be much lower and it also depends upon the anode, electrolyte, other chemicals used in the cell etc.

### Table1: Specific Capacity of Cathode Materials

Reaction Atomic No: Atomic Weight Valency Specific Capacity (mAh/g)
H/H(+) 1 1.008 1 26588
Li/Li(+) 3 6.94 1 3861
Na/Na(+) 11 22.990 1 1166
Mg/Mg(2+) 12 24.310 2 2205
Al/Al(3+) 13 26.980 3 2980
K/K(+) 19 39.10 1 685
Ca/Ca(2+) 20 40.08 2 1337
Zn/Zn(2+) 30 65.39 2 820
Pb/Pb(2+) 82 207.2 2 259

The following bar graph summarizes the specific capacity of all Metals given above.

## Spoofing Multicast packet from another interface.

This is the scenario. I have a working ethernet device eth0 with an IP address 192.168.1.x. There is one more special interface in the system, say if1 which is connected to another network. That network is mainly used for transmitting multicast data.

Received multicast data has to be processed by a userland application. Due to some reason I want to project this multicast data as unicast, with a destination MAC as the MAC address of eth0 and destination IP address as the IP address of eth0. So, the application feels that the multicast is coming through eth0 interface. This has to be done for UDP packets to port 10000 only.

This is achieved by changing the driver of if1 interface the following way.

```#include <ltnet/checksum.h>
#include <ltlinux/inetdevice.h>
```

```static struct net_device *eth_dev;
static u32 local_ip;
static int init_done = 0;
```

```static void init_fwd_process(struct net_device* net_dev)
{
/* Here net_dev is the if1 device */

if(likely(init_done == 1))
return;

/* Find out the net_device of eth0 */
eth_dev = dev_get_by_name(&init_net, "eth0");

/* First find out the IP address of eth0 */
ifa = ((struct in_device*)eth_dev->ip_ptr)->ifa_list;

init_done = 1;
}
```

```/* Initial 2 octets are used by the driver, for this particular driver */
#define ETH_DST_OFF 2
#define ETH_SRC_OFF 16
#define ETH_TYPE_OFF 30
#define IP_HDR_OFF 32
#define IP_TYPE_OFF (IP_HDR_OFF + 9)
#define IP_DSTABSOLUTE_OFF (IP_HDR_OFF + 16)
#define UDP_HDR_OFF (IP_HDR_OFF + 20)
#define UDP_DPORT_OFF (UDP_HDR_OFF + 2)

#define IP_TYPE_UDP 0x11

/* These are relative to IP packet */
#define IP_SRC_OFF 12
#define IP_DST_OFF 16
#define IP_CS_OFF 10
#define UDP_CS_OFF (20 + 6)

/* UDP Port we are interested in, 10000 in this case */
#define UDP_PORT 10000

static int fwd_mcast_packet(struct sk_buff *skb, unsigned char *data,
int len, struct net_device  *net_dev)
{
int n;
u16 c;
unsigned char* eth_src;
unsigned char* eth_type;
unsigned char* ip_hdr;
unsigned char* ip_type;
u32 ip_dst;
u16 udp_dst;
unsigned char hdr_802_3[14];

do {
init_fwd_process(net_dev);

eth_src = data + ETH_SRC_OFF;
eth_type = data + ETH_TYPE_OFF;
ip_hdr = data + IP_HDR_OFF;
ip_type = data + IP_TYPE_OFF;
ip_dst = (u32)(ntohl(*((u32 *)(data + IP_DSTABSOLUTE_OFF))));
udp_dst = (u16)(ntohs(*((u16 *)(data + UDP_DPORT_OFF))));

/* only IP packet */
if((*(u16 *)eth_type) != (htons(ETH_P_IP)))
break;
/* only UDP */
if(*ip_type != IP_TYPE_UDP)
break;
/* only multicast */
if(!(ntohl(ip_dst) & 0xe0000000))
break;
/* only interesting port */
if(ntohs(udp_dst) != UDP_PORT)
break;

/* We are interested in this packet
Let other packets go through the usual path */
/* destination is eth0 */
/* source is the original one */
memcpy(&hdr_802_3[6], eth_src, 6);
/* ethernet type is the original one */
memcpy(&hdr_802_3[12], eth_type, 2);

/* for aligning IP header on 16 byte */
skb_reserve(skb, 2);
/* copy the generated MAC header */
memcpy(skb_put(skb, 14), hdr_802_3, 14);

/* copy from the original IP header onwards */
n = len - IP_HDR_OFF;
memcpy(skb_put(skb, n), ip_hdr, n);

skb->protocol = htons(ETH_P_IP);
skb->pkt_type = PACKET_HOST;
skb_reset_mac_header(skb); /* just like eth_type_trans */
skb_pull(skb, ETH_HLEN);

/* Destination IP address should be local_ip,
Here skb->data is the beginning of IP header */
memcpy(&skb->data[IP_DST_OFF], &local_ip, 4);

/* regenerate IP checksum */
skb->data[IP_CS_OFF] = 0;
skb->data[IP_CS_OFF + 1] = 0;
c = ip_fast_csum(skb->data, 5);
memcpy(&skb->data[IP_CS_OFF], &c, 2);

/* Only clear the UDP checksum */
skb->data[UDP_CS_OFF] = 0;
skb->data[UDP_CS_OFF + 1] = 0;

/* call the main receive function */
netif_rx(skb);

return len;
}while(0);

return -1;
}

/* Inside the main packet receive function of driver */
if(fwd_mcast_packet(skb, (unsigned char *)data, length, net_dev) > 0) {
/* This packet has been already forwarded to IP stack,
Just do no do anything */
return;
}
```

## Can we avoid Energy Storage

There have been a lot of focus about energy storage these days coupled along with solar and wind. As a coin has two sides, Energy Storage has both pros and cons.

Some of the main concerns I could gather are:

• Prohibitively Expensive Capital Cost:
Energy Storage systems are expensive to own. Cheapest solutions like Lead Acid Battery itself costs around \$200 per KWh.
• Usage of exotic Chemistries and Rare Materials:
Many of the materials used are rare and expensive, for example Platinum is used as a catalyst in Fuel cells, usage of composite materials in flywheels, rare earths in superconductors etc.
• Environmental issues:
Batteries use environmentally unfriendly chemicals. Prime examples are the usage of Lead and Cadmium. Extremely reactive metals like Sodium and Lithium also are used.
• Safety Issues:
Many of the fuel cells and batteries should be operated at high temperatures. Reactive metals like Sodium and Lithium have safety concerns.
• Limited Cycles:
Most of the batteries could only be used for a limited number of cycles, for example Lead Acid Batteries have a limit of around 800 cycles.
They could not be 100% discharged, Deep Cycle Batteries could go to around 20% charge
• Low Energy Density:
Energy Densities are very low compared to both fossil fuels and biofuels.
• Geographic location dependence: Especially for CAES and pumped hydro storage

Does that mean that we could dump the whole idea of energy storage itself? Hold on for a second, let us see what are the alternatives available.

What about maintaining the current status quo?
We are using fossil fules like petroleum, coal and natural gas to meet majority of our energy requirements. They have many advantages which could not be ignored for now, mainly comparatively cheap, excellent energy density, easy to store/carry wherever required etc. Most of the infrastructure required are already there.

To give an overview, currently huge amounts of fossil fuels are getting used. World usage of petroleum is around 86 Million Barrels per Day. To make it simple, 1000 barrels of oil is getting burnt every second !!!!! Coal usage is an astouding 6 Billion Metric Tonnes per year, that is 1 Metric Tonne per person. India alone uses around 3 Million Barrels of oil per day and 250 Million tonnes of coal every year.

So, if are ready to forget about pollution, climate change and expendable nature of fossil fuels, we still would be able to continue drinking petrol, eating coal and breathing natural gas. That is the only way to maintain current status quo.

Hydropower is really clean, should we use it?
Hydropwer is the single largest renewable energy source currently under use. It accounts for 20% of both India’s and World’s electricity production. Hydropower has a total potential to supply around 100% of installed capacity (around 3000GW) of the world. So water could barely lift the current load.
Hydro Potential of India
Hydro Potential of World

Nuclear Power Scenario
Nuclear Power provides around 14% of World’s electricity. Nuclear enjoyed lots of interests until recently. But after the Japanese Fukushima Nuclear Crisis, serious safety concerns have been raised.

How about using biomass like agricultural by-products, manure etc.
Biomass has got a huge potential and we should try to utilize them. A study says that India produces around 500 MMT of biomass per year and out of which around 150 MMT is surplus. This gives a potential of around 25000 MW electricity production for India.
Biomass Potential of India
But, looking carefully, biomass is really a low hanging fruit. It looks fantastic until biomass based systems try to go real mainstream. Once they reach the mainstream status, they could potentially create the following problems.

• Limited amount of biomass availability because they are mainly agricultural by-products. So further scaling up from the above numbers would be really difficult.
• Direct competition with food production for the availability of land if biomass production becomes a profitable business.
• Stepping upon forest land for the same reason.
• Difficult to use in transportation sector.

Can we complement the situation with Biofuels?
There are many different types of biofules available like bioethanol, biodiesel and biobutanol. Current main source of ethanol are sugar cane, and corn. Where as biodiesel could be produced from different oil sources like sunflower, coconut oil, palm oil etc. and also from Jatropha from marginal lands. But the best yield is given by different algae streams.
One study says that Jatropha based biodisel cound supply 22% of India’s petroleum demand.
Jatropha Potential of India

Considering the usage of land, it is essential to look at the overall efficiency from sunlight to biodiesel. It is practically less than 1%
Photosynthesis Efficiency

So, only algae based Biofules could reach sustainability. It is progressing but still it has not reached commercial status.
Other biofuel technologies like sugar cane ethanol, corn ethanol, palm oil and other biodiesel etc. have limited potential to fix the overall energy issues. Apart from that, they also contribute to the above mentioned problems: encroaching upon forest and farm land.

Our Earth is too hot inside. Geothermal energy.
Geothermal is another often discussed (pseudo) renewable energy and it could be considered as a baseload resource with no energy storage requirement. For commerical/quality power generation deep wells are required, on the other hand shallow wells could be used for heating purpose.
All these come with a few drawbacks. As per wikipedia, even though geothermal potential is much more than the current energy requirement, only a fraction of that is recoverable. Also quality varies through geographic locations. Apart from the economics, there are potential environmental drawbacks also. Chances of trapped carbon dioxide, sulphur dioxide etc. getting released to the environment is high. In addition to these gases toxic elements like Mercury, Arsenic etc. could get released. There have been concerns about increased earthquakes due to deep wells.
Environmental Effects of Geothermal Energy
Geothermal Resources

Wave Power, OTEC and Tidal Power
Wave Power, Tidal Power and Ocean Therman Energy Conversion (OTEC) have great energy potential. But they have not reached commercial status yet. Only pilot projects of a few MWs have been carried out so far.

As per Harvard University, Wind Energy has a potential of more than 40 times the current World energy consumption. Where as Earth receives around 6000 times Solar Energy compared to the energy consumption. Wind Power has already reached grid parity in many cases and solar is gearing towards that. Lots of reserach and investments are taking place to make them go mainstream.
Global Potential for Windpower
Windpower Potential
Solar Potential

So, Sustainability and Climate Change have defined a clear goal…… Reduce the above oil and coal usage numbers as much and as fast as possible. A very challenging problem, much more than any “Rocket Science” ever achieved.

Considering both the current state of technology development and overall potential to meet the global energy demand completely, only Solar and Wind could be considered for the top positions. But their sustainability depends upon Energy Storage.

So as far as Energy Storage is concerned, apart from biting the bullet no other solution is existing in the long run. There is no other way, but to fix all of the shortcoming of Energy Storage.

Edited on 08/08/2011
I received a comment about Solar Thermal systems. Solar could include both Photovoltaic and concentrated solar thermal systems also.

## Network throughput measurement using netcat

There are many network throughtput and performance measurement tools available. One of the most widely used one is “iperf”. But, I found “netcat” to be a very versatile and fantastic tool to do the same.

The only “extra” requirement is to have shell access to both sides, so that netcat could be used.

First install the required tools
`apt-get install netcat-traditional bwm-ng pv`

Considering “machine1” and “machine2” are the two systems on both side of the link. Do the following
``` machine1:\$ nc -l -p 5000 | pv > /dev/null machine2:\$ dd if=/dev/zero | pv | nc ip_address_or_hostname_of_machine1 5000 ```
Logic:
Netcat of machine1 opens a TCP listening socket and dumps the data to /dev/null. machine2 reads from /dev/zero and forwards that data to machine1 through netcat. Here, flow control is done by TCP stack and keeps the throughput just below the network link speed. Normally “pv” prints the pipe throughput in bytes, so multiply the real time value of “pv” by 8 to get the throughput in bits.

Tools like “bwm-ng” could be used to monitor the througput of the the interface instead of or along with “pv” also.

Some version of of netcat does not require “-p” in listening mode, so the comment could be “nc -l 5000” instead. In the sending side “cat” or “pv” could be used instead of “dd” also. But “dd” prints a nice summary when it is interrupted.

Of course, this is not completely one directional because TCP acknowledgements would be forwarded from machine1 to machine2, but that is much smaller compared to the data flowing in the forward direction.

If we have the liberty of having more shells, one more pair of netcat sessions could be opened in the reverse direction so that simultaneous/full duplex throughput could be measured.

I used this method consistently with Gigabit Ethernet and WiFi many times.

## Kerosene vs. Klean. Lighting up rural India: Cost and Emission Analysis

“Every block of stone has a statue inside it and it is the task of the sculptor to discover it” – Michelangelo

As of now, there are around 1.5 Billion people in the world without access to electricity grid, out ot which the share of India would come to around 400 Million people or around around 100 Million families. Majority of them live in the 80000 or so non grid connected villages in India.

They all depend mainly on Kerosene lanterns as the source of light. That makes Kerosene a very sensitive commodity in India. Kerosene is sold as a subsidized fuel in Government run ration shops for the poor people. Currently it is sold for around Rs. 12.50 per litre, but government gives around Rs.19.60 as subsidy on top of that to meet the actual open market price of around Rs. 32.00 Poor families are eligible to get around 6 lites per month at this subsidized rate.

Around 12 Billion litres of Kerosene are supplied to Ration shops annually and as much as 40% of that which is around 5 Billion litres are getting stolen to black market. The money lost by Indian government is around Rs. 10000 Crore (US\$ 2.2 Billion) in subsidy itself. That gives around 7 Billion litres for the actual use.

There is another dimension for the “lost” kerosene. It is mainly used to adulterate petrol and diesel fuel. Adulterated petrol and diesel causes less mileage, higher maintenace cost, higher smoke and particulate pollution and emission.

## Kerosene Usage Statistics

Summarizing Kerosene usage, Carbon Dioxide Emission and actual costs data.

### Table1: Kerosene Statistics

Usage 7 Bn Litres Black 5 Bn Litres Total 12 Bn Litres
Energy Content KWh 70 Bn 50 Bn 120 Bn
CO2 Emission 17.5 MMT 12.5 MMT 36 MMT
Total Cost
(Rs 32.00/Litre)
INR 22400 Cr
USD 5000 Mn
INR 16000 Cr
USD 3560 Mn
INR 38400 Cr
USD 8540 Mn
Subsidized Cost
(Rs 12.50/Litre)
INR 8750 Cr
USD 1950 Mn
INR 6250 Cr
USD 1390 Mn
INR 15000 Cr
USD 3340 Mn
Govt. Subsidy
(Rs 19.60/Litre)
INR 13720 Cr
USD 3050 Mn
INR 9800 Cr
USD 2180 Mn
INR 23520 Cr
USD 5230 Mn

* Assuming: kerosne has an energy density of 10KWh/36MJ per Litre and it produces 2.5Kg of CO2 per Litre. USD 1.00 is around INR 45.00

* CO2 emission of India is around 1800 MMT, so this figure is around 2% of that.

## Kerosene Lamp Efficiency

As per a study conducted by Lawrence Berkey National Labaratories, kerosene lamps energy consumption and light output vary a lot. In fact, a lot of kerosene is evaporated through the wick without getting burnt. Typical kerosene lanterns use around 5mL to 42mL of kerosene per hour, whereas light outputs vary from around 8 Lumens to 67 Lumens. This corresponds to light efficiency of 935 Lumen.Hour/Litre to 1914 Lumen.Hour/Litre. This leads to an energy efficiency of just 0.1 to 0.2 Lumen/Watts.

As a comparison, even an average incandescent lamp which many countries want to ban is more than 50 times better than these kerosene lamps. !!!!! To put it better, kerosene lamps are the costiest and dirtiest way to generate the same light output.

Apart from wastage of fuel, other problems like smoke, safety, burning hazard, pollution etc. associated with kerosene lamps are not discussed here. Also cost of kerosene lamps, running cost to buy wicks etc. are not mentioned.

Assuming average of around 1428 Lumen.Hour/Litre of Kerosene and 7 Billion Litres of usage, the total light produces is around 10000 Billion Lumen.Hours

### Table 2: Electricity requirement from a baseload plant to generate the same light

Light Source Incandescent
10 lumens/Watt
Fluroscent
60 lumens/Watt
LED
100 lumens/Watt
Energy Usage
KWh/Year
1000 Mn 166 Mn 100 Mn
Energy Usage
KWh/Day
2750 x 1000 455 x 1000 275 x 1000
Equivalent
114 MW 18.9 MW 11.4 MW

This tables summarizes the power requirement of Incandescent, Fluorescent and Light Emitting Diode to produce the same amount of light. Light is normally required only in the evening time for around 5 hours. So 5 times peak power requirement could be assumed during evenings, where as no power is required for the rest of the time.

That means with a power plant of 1000 MW operating in the evening for 5 hours and using standard CFL lighting, 10 times more light could be delivered to the same people. (18.9 MW x 5 x 10 times light) This is not even 1% of the electricity production capacity of India. That is around 600 lumens of light per family compared to the meager 60 lumens which a kerosene lamp could provide.

### Table 3: Power produced if the same kerosene is diverted to baseload power plants

7 Bn Litres
Usage
12 Bn Litres
Usage
Energy Content 70 Bn KWh 120 Bn KWh
Energy Content
in MW.Year
7985 MW.Year 13689 MW.Year
Standard DG Output
at 20% efficiency
1600 MW.Year 2700 MW.Year
Combined Cycle Gas Turbine Output
at 50% efficiency
4000 MW.Year 6800 MW.Year

This shows that the same kerosene could drive a 6800 MW Combined Cycle Gas Turbine based Power plant continuously for one year.

## Using Clean Technologies for the same lighting scenario

As seen from above, to produce 10 times more light output using CFL, we require 4.55 Million KWh of electricity per day (189 MW baseload power plant equivalent).

Using Solar Photovoltaic
Being a tropcial country, India gets very good solar insolation of 5.5 KWh/m2/day or 2000KWh/m2/year average. Generating 4.55 Million KWh requires 830 MW Solar Panel. Currently solar modules are available below \$2 per Watt. Maximum Power Point Trackers and inverters are available at around \$0.60 per Watt and \$0.75 per Watt respectively. Considering around \$4 per Watt for all of these, it would lead to \$3320 Million

Using Small Wind Power
With a capacity factor of 25%, the name plate capacity required to generate 189 MW of baseload power is 756 MW. Normally 2MW turbines are available at around \$2 Million per MW. But small ones which generate a few KW are more expensive at around \$4 per Watt. That comes to \$3024 Million

Storage using Batteries
Standard Lead Acid Batteries cost around \$200 per KWh. Assuming a depth of dischare of 50% it is required to have double the name plate capacity, so assuming \$400 per KWh for the name plate capacity of 4.55 Million KWh, the requirement would be around \$1820 Million.

Other Costs
There are many other expenditures associated like installations etc. In this case, many of them could be shared among different users. Assuming a cost of \$40 associated with these, the total cost for 100 Million users would be \$4000 Million.

### Table 4: Summary of Clean Technology Costs

Energy Requirement
per Day
4.55 Mn KWh
Using Solar Systems 830 MW
at \$4.00 per Watt
\$3320 Mn
Using Windpower Systems 756 MW
at \$4.00 per Watt
\$3024 Mn
Storage Batteries 4.55 Mn KWh
at \$200 per KWh
\$1820 Mn
Other Miscellaneous 100 Million users
at \$40 per user
\$4000 Mn
Total Using Solar \$9140 Mn
Total using Wind \$8844 Mn

## Conclusion:

To rephrase what Michelangelo said: “Money is there with the people, it is the task of the Government to reprioritize it”

## References

http://www.interfaceflor.eu/internet/web.nsf/webpages/536_IN.html?OpenDocument&

http://articles.timesofindia.indiatimes.com/2011-01-30/special-report/28373372_1_kerosene-prices-ration-shops-kilolitre

http://articles.timesofindia.indiatimes.com/2011-01-27/india/28363076_1_kerosene-ration-shops-fuel-mafia

http://evanmills.lbl.gov/pubs/pdf/offgrid-lighting.pdf Table 1/Page 4

http://solarbuzz.com/facts-and-figures/retail-price-environment/module-prices

http://www.popularmechanics.com/home/improvement/energy-efficient/4321836

Edited on 26/07/2011:
I got a couple of comments about using biomass. Actually biomass gasifiers or digesters could be used to produce electricity also. One advantage of using this methods is that electricity could be generated as and when it is required. In many cases, this could be cost effective compared to solar or wind coupled with energy storage. Around 200 Million tonnes of biomass is used in India for cooking purpose itself.

## Problems of Lunar Solar Power

There have been a lot of proposals about having Solar Power Stations on Moon. The plan is to create a belt of solar modules around 11000km equator. The power will be taken to Earth using Microwave beams. After going through some of their ideas, I thought it was not an idea at all. Some of them were very basic so that I do not know how they over come them. Consider the following points.

1. Earth receives 6000 times solar energy than we require, so there is no need to look outside.
2. http://en.wikipedia.org/wiki/Space-based_solar_power#On_the_Moon These ideas are not new. They came back in around 1970.
3. Current launch system costs are exorbitantly high, somewhere around \$5000 per kg. Until systems like space elevators etc. become commercially available, it would be really expensive to launch these systems. Also note that, Moon does not have an atmosphere but it has a gravity of around 1.62 m/s2 which is 16% of Earth. So reverse thrust rockets would have to be used to land anything on Moon. Also these rockets and their fuel also have to be taken from Earth at the same cost of \$5000 per kg.
4. Actually only one side of Moon is visible, and Moon has a day of around 29 days. So for 14 days when the Sun is on the other side of the Moon, that means around what we call as New Moon times, no power or very little power could be sent to Earth.
5. As per Wikipedia article, microwave beam power is around 23mW/cm2 which 25% of Solar radiation. So large area rectennas have to be used.
6. Remember that Apollo program cost was \$25.4 Billion actually (1973 report) but estimated cost in 2005 was around \$170 Billion. (from Wikipedia)

Currently solar modules prices are going down very fast and very soon they would reach the landmark \$1 per Watt level. There have been a lot of work going on in that area. Even Printed Solar Cells work is progressing . If these solar panel could be depoyed on everywhere on our own Earth, why do we need to taken them to Moon at all?